(x+3)(2x+4)=2x^2

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Solution for (x+3)(2x+4)=2x^2 equation: 


Simplifying
(x + 3)(2x + 4) = 2x2

Reorder the terms:
(3 + x)(2x + 4) = 2x2

Reorder the terms:
(3 + x)(4 + 2x) = 2x2

Multiply (3 + x) * (4 + 2x)
(3(4 + 2x) + x(4 + 2x)) = 2x2
((4 * 3 + 2x * 3) + x(4 + 2x)) = 2x2
((12 + 6x) + x(4 + 2x)) = 2x2
(12 + 6x + (4 * x + 2x * x)) = 2x2
(12 + 6x + (4x + 2x2)) = 2x2

Combine like terms: 6x + 4x = 10x
(12 + 10x + 2x2) = 2x2

Add '-2x2' to each side of the equation.
12 + 10x + 2x2 + -2x2 = 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
12 + 10x + 0 = 2x2 + -2x2
12 + 10x = 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
12 + 10x = 0

Solving
12 + 10x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + 10x = 0 + -12

Combine like terms: 12 + -12 = 0
0 + 10x = 0 + -12
10x = 0 + -12

Combine like terms: 0 + -12 = -12
10x = -12

Divide each side by '10'.
x = -1.2

Simplifying
x = -1.2

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